20a^2+16a=48

Solution for 20a^2+16a=48 equation:

20a^2+16a=48

We move all terms to the left:

20a^2+16a-(48)=0

a = 20; b = 16; c = -48;
Δ = b2-4ac
Δ = 162-4·20·(-48)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-64}{2*20}=\frac{-80}{40}
=-2
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+64}{2*20}=\frac{48}{40}
=1+1/5
$